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IAL Statistics 1: Discrete Random Variables Exam Questions

10 exam-style questions · 82 marks · about 100 minutes · full mark scheme

Specification: S1 discrete random variables

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About this chapter

Discrete random variables brings together probability and averages. A question gives a table or a formula for the probabilities, and asks for missing values, the mean, the variance, or the distribution of a new variable built from the old one. The last part is often a game, where you must list every way to win.

This chapter covers probability distributions and probability functions, cumulative distribution functions, E(X), E(X²) and Var(X), linear functions of a random variable, the discrete uniform distribution, finding unknown probabilities from two conditions, and combining independent observations.

The ten questions

  • Q1 (5 marks): a probability function k(x+1): show k = 1/14, then an exact E(X) and a probability.
  • Q2 (5 marks): two unknown probabilities from the total of 1 and a given E(X).
  • Q3 (5 marks): recover a distribution from its cumulative distribution function.
  • Q4 (5 marks): E(5 − 2X), Var(5 − 2X) and E(X²) from a given mean and variance.
  • Q5 (5 marks): a fair 12-sided die: the uniform distribution, then Y = 4X − 3.
  • Q6 (12 marks): a table mixing p(x) and F(x) with unknowns, show Var(X) = 1.46, then E(Y²) and two observations.
  • Q7 (12 marks): a red and a blue four-sided die: sums, comparisons, and the distribution of the difference.
  • Q8 (11 marks): a symmetric distribution, a uniform one, and a linear function W = aX + b fitted to both.
  • Q9 (10 marks): points scored in a game: E(X) and Var(X), then the chance of reaching a prize total in the remaining rounds.
  • Q10 (12 marks): a cumulative distribution function with k in it: show k = 2, the distribution, E(X), an inequality and Var(5 − 3X).

Key skills tested

Probability distributions. Every probability lies between 0 and 1 and they add to 1, which finds an unknown.

Probability functions. For a formula such as k(x+1), substitute each value of x, add, and set the total equal to 1.

Cumulative distribution. F(x) = P(X ≤ x), so P(X = x) = F(x) − F(x − 1). For whole-number X, F(2.7) equals F(2).

Expectation. E(X) = Σ x P(X = x), and E(X²) = Σ x² P(X = x).

Variance. Var(X) = E(X²) − [E(X)]². E(X²) is not the same as [E(X)]².

Linear functions. E(aX + b) = aE(X) + b, and Var(aX + b) = a² Var(X): the b disappears and the a is squared.

Discrete uniform. For n equally likely values 1 to n, E(X) = (n+1)/2 and Var(X) = (n² − 1)/12.

Unknown probabilities. The total of 1 and a given E(X) give two simultaneous equations.

Combining observations. Independent observations multiply. List every pair that gives the event; a sample space helps.

Key skills page for IAL Statistics 1 Chapter 6, Discrete Random Variables: nine skill cards from probability distributions to combining observations, with a skills map

Worked example

Question 1 from this chapter. P(X = x) = k(x+1) for x = 1, 2, 3, 4. (a) Show that k = 1/14. (b) Find the exact value of E(X). (c) Find P(X ≥ 3).

(a) The probabilities are 2k, 3k, 4k and 5k. They add to 1, so 14k = 1 and k = 1/14.

(b) E(X) = (1 × 2 + 2 × 3 + 3 × 4 + 4 × 5) ÷ 14 = 40 ÷ 14 = 20/7.

(c) P(X ≥ 3) = P(X = 3) + P(X = 4) = (4 + 5) ÷ 14 = 9/14.

The question asks for an exact E(X), so 20/7 should stay a fraction rather than become 2.86.

Worked solution to Statistics 1 Chapter 6 Question 1: the probabilities 2k, 3k, 4k and 5k give k equals one fourteenth, E(X) equals twenty sevenths, and P(X at least 3) equals nine fourteenths

Seen on real papers
Every question in our booklets is original. These are the recent papers where each question type has appeared.

  • June 2024, Q2: a distribution where E(X²) had to be shown before the variance, then a linear function aX + b and the outcomes of a game, as in Q6, Q8 and Q9.
  • June 2022, Q5: two unknown probabilities from the total and E(X), a standard deviation, and games needing several probabilities multiplied, as in Q2 and Q9.

Where marks are lost

  • a instead of a². The most common error in June 2024 was multiplying Var(X) by a rather than a² when finding the variance of aX + b.
  • Skipping E(X²) in a show that. In June 2024 students lost marks for not showing E(X²) when asked to show a variance, since it could be worked backwards from the answer.
  • Variance or standard deviation? In June 2022 many calculated the variance when the question asked for the standard deviation.
  • The missing equation. In June 2022 many wrote the E(X) equation but not the sum of probabilities equal to 1, so could not find both unknowns.
  • Too few probabilities multiplied. In June 2022 an event needed three probabilities multiplied, and most multiplied only two.

Common questions

Is E(X²) the same as [E(X)]²?
No. E(X²) squares each value before weighting; [E(X)]² squares the mean. Their difference is the variance.

Why does the constant disappear in Var(aX + b)?
Adding a constant shifts every value by the same amount, which moves the mean but does not change the spread.

How do I get probabilities from a cumulative distribution function?
Subtract consecutive values: P(X = x) = F(x) − F(x − 1).

Where this chapter leads

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